Ushtrimi 4

Dimë që: $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ si dhe $\sqrt[3]{\frac{a}{b}} = \sqrt[3]{\frac{a}{b}}$. $\sqrt{\frac{9}{25}} = \frac{\sqrt{9}}{\sqrt{25}} = \frac{3}{5}$.

Gjeni sipas shembullit:

a $\sqrt{\frac{16}{49}}$; $\sqrt{\frac{25}{81}}$; $\sqrt{\frac{4}{121}}$; $\sqrt{\frac{49}{81}}$; $\sqrt{0,16}$

b $\sqrt[3]{\frac{8}{27}}$; $\sqrt[3]{\frac{1}{8}}$; $\sqrt[3]{\frac{64}{125}}$; $\sqrt[3]{\frac{1}{64}}$